If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4j^2-9j-9=0
a = 4; b = -9; c = -9;
Δ = b2-4ac
Δ = -92-4·4·(-9)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-15}{2*4}=\frac{-6}{8} =-3/4 $$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+15}{2*4}=\frac{24}{8} =3 $
| −24−125p=375p | | 18r+4r-21r+1=17 | | -480x^2-720x=84 | | 2x+3(x+5)=(x+3) | | 2x+3(x+4)=(x+3) | | 7x-11x=-19-25 | | s^2-23s+22=0 | | 2a-6=204 | | F(0)=4^n | | -2(p+3)=-2 | | 3x-8+4x=4x-7 | | 6.6g+6=2.6g+14 | | -6-(-36)=x/9 | | 12m-112=1,000 | | 7x+3=2x+x-3 | | 7.9-0.7x=1.6 | | F(3)=4^n | | 5(5x-1)-4=21x+7 | | 19a-12-4/8=-57 | | 4x-10=-2(x+3) | | 20°=46x-440x | | 3x(2x+3)=2x+9 | | 4x+8=9x+-8 | | 2x+20+3x+4x-20=180 | | F(-2)=-5n+7 | | x+3(x4)=5(x+2) | | 2(y+8)-9=-7 | | f(-1/2)=-2(-1/2)+3 | | h/6-`1=-3 | | 20-3x+6x-18=35 | | 162=13b-7 | | 4x-(5x-10)=10 |